Submission #2640116


Source Code Expand

#include<iostream>
#include<vector>
#include<algorithm>
using namespace std;

int count_inversions(int n, vector<pair<double, int > > p) {

    int res = 0;
    vector<int> s(n+1, 0);
    for(int k=0; k < n; k++) {
        int c = 0;
        int u = p[k].second;
        while(u > 0) {
            c += s[u];
            u -= u & (-u);
        }
        u = p[k].second;
        while(u <= n) {
            s[u]++;
            u += u & (-u);
        }
        res += k - c;
    }

    return res;
}

double find_median(int n, vector<int> a, vector<int> b, vector<int> c) {
    int m = n * (n - 1) / 2, target_inversions;

    if (m % 2 == 1)
        target_inversions = (m - 1) / 2;
    else
        target_inversions = m / 2;

    vector<pair<double, int> > slope(n);
    for(int i=0; i < n; i++) {
        slope[i] = {-a[i] * 1.0 / b[i], i};
    }
    sort(slope.begin(), slope.end());

    vector<pair<double, int> > p(n);

    double inf = 1e9;
    double sa = -inf, sb = inf, s;
    int n_steps = 300;

    for(int step=0; step < n_steps; step++) {
        s = (sa+sb) / 2;
        for(int i=0; i < n; i++) {
            int j = slope[i].second;
            p[i] = {(-a[j] * s + c[j]) / b[j], i + 1};
        }
        sort(p.rbegin(), p.rend());

        int c = count_inversions(n, p);

        if (c > target_inversions) {
            sb = s;
        }
        else {
            sa = s;
        }
    }
    return sa;
}

double find_median_exhaustive(int n, vector<int> a, vector<int> b, vector<int> c) {
    int m = n * (n - 1) / 2, p;

    if (m % 2 == 1)
        p = (m-1) / 2;
    else
        p = m / 2 - 1;
    vector<double> t(m);

    int k=0;
    for(int i=0; i<n; i++) {
        for(int j=i+1; j<n; j++) {
            double d, dx, dy;
            d  = a[i] * b[j] - a[j] * b[i];
            dx = c[i] * b[j] - c[j] * b[i];
            dy = a[i] * c[j] - a[j] * c[i];
            t[k] = dx / d;
            k += 1;
        }
    }
    sort(t.begin(), t.end());
    return t[p];
}



int main() {
    int n;
    cin >> n;
    vector<int> a(n), b(n), c(n);
    for(int i=0; i<n; i++)
        cin >> a[i] >> b[i] >> c[i];

    double x, y;
    x = find_median(n, a, b, c);
    y = find_median(n, b, a, c);

    cout.precision(17);
    cout << x << " " << y << endl;
    return 0;
}

Submission Info

Submission Time
Task E - CARtesian Coodinate
User Martial
Language C++14 (GCC 5.4.1)
Score 0
Code Size 2406 Byte
Status WA
Exec Time 2597 ms
Memory 3236 KB

Judge Result

Set Name Sample All
Score / Max Score 0 / 0 0 / 800
Status
AC × 2
WA × 1
AC × 18
WA × 17
Set Name Test Cases
Sample s1.txt, s2.txt, s3.txt
All 01.txt, 02.txt, 03.txt, 04.txt, 05.txt, 06.txt, 07.txt, 08.txt, 09.txt, 10.txt, 11.txt, 12.txt, 13.txt, 14.txt, 15.txt, 16.txt, 17.txt, 18.txt, 19.txt, 20.txt, 21.txt, 22.txt, 23.txt, 24.txt, 25.txt, 26.txt, 27.txt, 28.txt, 29.txt, 30.txt, 31.txt, 32.txt, s1.txt, s2.txt, s3.txt
Case Name Status Exec Time Memory
01.txt AC 2565 ms 3236 KB
02.txt AC 2545 ms 3236 KB
03.txt WA 2549 ms 3236 KB
04.txt WA 2520 ms 3236 KB
05.txt WA 2577 ms 3236 KB
06.txt AC 2560 ms 3236 KB
07.txt AC 2566 ms 3236 KB
08.txt WA 2571 ms 3236 KB
09.txt WA 2593 ms 3236 KB
10.txt WA 2536 ms 3236 KB
11.txt AC 2545 ms 3236 KB
12.txt AC 2569 ms 3236 KB
13.txt WA 2560 ms 3236 KB
14.txt WA 2553 ms 3236 KB
15.txt WA 2564 ms 3236 KB
16.txt AC 2533 ms 3236 KB
17.txt AC 2589 ms 3236 KB
18.txt WA 2538 ms 3236 KB
19.txt WA 2597 ms 3236 KB
20.txt WA 2544 ms 3236 KB
21.txt AC 1118 ms 3236 KB
22.txt AC 1118 ms 3236 KB
23.txt WA 2558 ms 3236 KB
24.txt WA 2565 ms 3236 KB
25.txt WA 2578 ms 3236 KB
26.txt AC 2572 ms 3236 KB
27.txt AC 1 ms 256 KB
28.txt AC 1 ms 256 KB
29.txt AC 1 ms 256 KB
30.txt WA 1 ms 256 KB
31.txt AC 1 ms 256 KB
32.txt AC 1 ms 256 KB
s1.txt AC 1 ms 256 KB
s2.txt WA 1 ms 256 KB
s3.txt AC 1 ms 256 KB